Question

The equation of trajectory of a projectile is given as
2
Y=2x-
The maximum height of projectile is
(Symbols have usual meanings and SI unit)
(1) 4 m
(2) 1 m
(3) 2 m
(4) 10 m​

Answer 1

Answer:

the data given is that the height is maximum and hence the velocity of the vertical component is zero

Answer 2

Answer:

(3) 2 m

Explanation:

If we assume that

Y = 2 x- x²/2

We know that to maximize we have to find derivative with respect to the x and it should be zero.

$\dfrac{dY}{dx}=0$

Y = 2 x- x²/2

$\dfrac{dY}{dx}=2-x$

$\dfrac{dY}{dx}=0$

2- x =0

x= 2 m

So the value of Y at x=2 m

Y = 2 x- x²/2

Y = 2 ₓ 2 - 2²/2

Y= 4 - 2

Y= 2 m

So the option 3 is correct.

(3) 2 m