Question

the equation of trajectory of a projectile is given as y is equals to 2 x minus x square upon 2 the maximum height of a projectile is symbols have usual meaning and SI unit​

Answer 1

Answer:

1/2 m

Explanation:

Y = (2x - x²)/2

dy/dx = (2 - 2x)/2

=> dy/dx = 1 - x

putting dy/dx = 0

=> 1 -x = 0

=> x = 1

d²y/dx² =  - 1

=> x = 1 will give maximum value of Y

Y at x = 1

Y = (2*1  - 1²)/2

=> Y = 1/2

Max height = 1/2 m   or  1/2 M⁰L¹T⁰