Question

The equation of trajectory of a projectile is given by
y = 4x -[(40x^2) ÷39], where y is vertically upwards. If R

is range and is angle of projection from horizontal,
then value of Rtano is (x and y are in m)
(1) 3.9 m
(2) 15.6 m
(3) 11.7 m
(4) 14.2 m​

Answer 1

we know

y=ax+b×^2

here

tan@=4

R=A/B

=4/40×39

HENC5

RTAN@=3.9×4

=15.6

hope this helps. ....

Answer 2

we know

y=ax+bx^2

here

tan@=4

R=A\B

=4\40x39

Hence5

RTAN@=3.9×4

=15.6