Question

The equation of trajectory of a projectile is y = 10x - (5/9) x2. if we assume g =10 ms-2, the range of projectile (in meter) is

Answer 1

Answer:

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Answer 2

The range of the projectile is 18 m.

Given,

The equation of trajectory of a projectile is y = 10x - (5/9) x². The value of g is taken as g = 10 m/s².

To Find,

The range of the projectile.

Solution,

The equation of trajectory of a projectile is

y = 10x - (5/9) x²

Now, for the range of projectile the value of x is R and y is 0.

So, substituting the values in the equation

0 = 10R - (5/9)R²

R(10-(5/9)R) = 0

10-(5/9)R = 0

5R = 10×9

R = 18 m

Hence, the range of the projectile is 18 m.

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