Question

The equation of trajectory of a projectile is y=ax-bx^(2) where x and y axes are along horizontal and vertical directions respectively.The range of the projectile is

Answer 1

Answer:

Explanation:

The trajectory of a projectile in a vertical plane is y=ax-bx2,where a and b are constants,and x and y are respectievly the horizontal and the verticaldistanceof the projectile from the point of projection