Question

The equation of trajectory of projectile is given by $y = \frac{x}{\sqrt{3}} - \frac{gx^{2}}{20}$, where $x\ and\ y$ are in metre. The maximum range of the projectile is
(a) $\frac{8}{3}$ m
(b) $\frac{4}{3}$ m
(c) $\frac{3}{4}$ m
(d) $\frac{3}{8}$ m

Answer 1

Pta nii sorry.. Google