Physics, asked by deepakchaudhry4218, 1 year ago

The equation of trajectory of projectile is given by y = \frac{x}{\sqrt{3}} - \frac{gx^{2}}{20}, where x\ and\ y are in metre. The maximum range of the projectile is
(a) \frac{8}{3} m
(b) \frac{4}{3} m
(c) \frac{3}{4} m
(d) \frac{3}{8} m

Answers

Answered by sarthakkaushik85
0

Pta nii sorry.. Google

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