Question

The equation of transverse vibration of stretched string is given by y= 0.00327sin(72.1x-2.72t)m

, in which the numerical constants

are in SI units. Evaluate (i) Amplitude (ii) Wavelength (iii) Frequency

and (iv) velocity of the wave​

Answer 1

Explanation:

Amplitude = 0.00327m

wavelength = 2.72m

frequency = $\frac{2\pi }{w}$ = 0.234m

velocity of wave = $\frac{w}{k}$ = $\frac{2.72}{72.1}$ = 0.0377 ms-1

hope it helps.