Question

the equation
passes through
the point (3,2) and (a,b)​

Answer 1

HERE IS YOUR ANSWER FRIEND:

(2x+0,20+y)=(3,2)

(2x,2y)=(3,2)

x=6,y=4

Thus, A=(6,0) and B=(0,4)

Slope of line AB=(4−0)/(0−6)=4/−6=−2/3

Slope of line AB=(4−0)/(0−6)=4/−6=−2/3And let (x1,y1)=(6,0)

Slope of line AB=(4−0)/(0−6)=4/−6=−2/3And let (x1,y1)=(6,0)So, the required equation of the line AB is given by

Slope of line AB=(4−0)/(0−6)=4/−6=−2/3And let (x1,y1)=(6,0)So, the required equation of the line AB is given byy−y1=m(x−x1)

Slope of line AB=(4−0)/(0−6)=4/−6=−2/3And let (x1,y1)=(6,0)So, the required equation of the line AB is given byy−y1=m(x−x1)y−0=(−2/3)(x−6)

Slope of line AB=(4−0)/(0−6)=4/−6=−2/3And let (x1,y1)=(6,0)So, the required equation of the line AB is given byy−y1=m(x−x1)y−0=(−2/3)(x−6)3y=−2x+12

Slope of line AB=(4−0)/(0−6)=4/−6=−2/3And let (x1,y1)=(6,0)So, the required equation of the line AB is given byy−y1=m(x−x1)y−0=(−2/3)(x−6)3y=−2x+122x+3y=12

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