Question

The equation root(3)sin x + cos x = 4 has
(A) Only one solution
(C) Infinitely many solutions
(B) Two solutions
(D) No solution

Only 3 is inside the root in the question​

Answer 1

Answer:

one and only solution of this equation

Answer 2

Answer:

Step-by-step explanation:

Its just simple as that

so at first :

multiply and divide it by 2 on LHS side;

so u get the equation as:

2[$\sqrt{3}$/2  (sinx )+1/2  (cosx)] {for ur understanding i had given space for sinx and cosx as its in numerator for not confusing u guys so.....}

after that

cos($\pi$/6)sinx+sin($\pi$/6)cosx=2   (since 2 from lhs side gets cancelled by for so remaining is 2.... And also cos ($\pi$/6)=root(3)/2 and sin ($\pi$/6)=1/2............ pi/6 is 30°)

then its in the form of sin(a+b)=sinaxcosb+cosaxsinb

therefore: final answer is sin[x+$\pi$/6]........

i hope u understand the steps.........dattebayo...