Question

the equation
$3x ^{2} + 12x +(n - 5) = 0$
has equal roots.find the value of n
​

Answer 1

Answer:

17

Step-by-step explanation:

for equal roots

∆=0 where ∆ is b^2-4ac

144-4(3)(n-5)=0

144= 12(n-5)

12 = n-5

n= 17

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Answer 2

Answer:

n=7

Step-by-step explanation:

For equal roots we have

=b^2-4ac=0

=12^2-4(3)(n-5)=0

=144-12n+60=0

=12n=84

=n=7