The equation that should be formed by decreasing each root of x²-3x+2=0 by 3 is
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answer. x^2+3x+2
Step-by-step explanation:
solving the eq.give roots (x-2) and (x-1) which is x=2,1 so decreasing 3 from both roots give -1 and -2 which also mean that it came when it will (x+1) and (x+2). multiplying (x+1)(x+2) to get new eq.
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Step-by-step explanation:
x^2-3x+2=0
x^2-2x-x+2=0
x(x-2)(x-1)=0
roots are x=2,1
decreasing each root
2-3 and 1-3
-1 and -2
new equation will be
(x+1)(x+2)
= x^ 2+2x+x+2
=x^2+3x+2
hope it helps you
pls mark as branly answer
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