Question

the equation the line passing through the point (1,2) and perpendicular to the line x+y+1=0 is.​

Answer 1

EXPLANATION.

Equation of line passing through point (1,2)

perpendicular to the line x + y + 1 = 0.

Slope of the perpendicular line = b/a.

Slope of line = x + y + 1 = 0 = 1.

$\sf \: \implies \: equation \: of \: line = (y - y_{1}) = m(x - x_{1})$

Point are = (1,2).

→ ( y - 2 ) = 1 ( x - 1 ).

→ y - 2 = x - 1

→ y - x = - 1 + 2.

→ y - x = 1.

More information.

Slope of parallel line = -a/b.

Equation of normal

$\sf \: (y - y_{1}) = \dfrac{ - 1}{m}(x - x_{1})$

Answer 2

Answer:

So, slope of line perpendicular to above line is 1. Line passes through the point (1,2). Therefore, equation of the required linens: y-2 = 1(x- 1) ⇒ y-x-1=0