Question

The equation to the locus of the points equidistant from the points (2,3) and (-2,5) is​

Answer 1

Step-by-step explanation:

Locus point =(x,y)

(x−2)

2

+(y−3)

2

=

(y−5)

2

+(x−4)

2

⇒(x−2)

2

+(y−3)

2

=(x−4)

2

+(y−5)

2

⇒x

2

+4−4x+y

2

+9−6y=x

2

+16−8x+y

2

+25−10y

⇒13−4x−6y=41−8x−10y

⇒−4x+8x−6y+10y=41−13

⇒4x+4y=28

⇒x+y=7.