Question

The equation to the locus points equidistant from the points (2,3) (-2,5) is

a)

2 4 0 x y −+=

b)

2 1 0 x y − − =

c)

2 4 0 x y + − = d)

2 1 0​

Answer 1

Answer:

ANSWER

Let the point be P(x,y) 

Distance between P(x,y) and A(1,3)=(1−x)2+(3−y)2=1+x2−2x+9+y2−6y=x2+y2−2x−6y+10

Distance between (x,y) and (−2,1)=(−2−x)2+(1−y)2=4+x2+4x+1+y2−2y=x2+y2+4x−2y+5

As the point (x,y) is equidistant from the two points, both the distances calculated are equal.

⇒x2+y2−2x−6y+10=x2+y2+4x−2y+5

⇒x2+y2−