Question

the equation to the pair of straight line passing through (2,2) and perpendicular to the pair of lines 4xy+2x+6y+3=0 is​

Answer 1

Answer:

xy -2x -2y +4 = 0

Step-by-step explanation:

4xy+2x+6y+3=0

This is the equation of combined lines.

So, equations of individual lines :

x + a = 0 & y + b = 0

A line perpendicular to x + a = 0 will be like y = k but since this line passes through (2,2) so y = 2 .

So one of the straight line is y - 2 = 0

Similarly, A line perpendicular to y + b = 0 will be like x = k but since this line passes through (2,2) so x = 2

So, one of the straight line is x - 2 = 0

So, required equation will be :

(x-2)(y-2) = 0

xy -2x -2y +4 = 0