the equation to tje locus of p for which the distance from p to (0,5) is double tje distance from p to x axis
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locus of a point P for ...
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The equation to the locus of a point P for which the distance from P to (0, 5) is double the distance from P to y-axis is · 3x2+y2+10y−25=0 · 3x2−y2+10y+25=0 · 3 ...
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Answer:
Correct option is
C
3x
2
−y
2
+10y−25=0
Let P(x,y) be an arbitrary point in X−Y plane.
Therefore distance of P from A(0,5) is
PA=
x
2
+(y−5)
2
...(i)
And distance of P from y axis.
d
y
=∣x∣
It is given that
2d
y
=PA
Or
2∣x∣=
x
2
+(y−5)
2
4x
2
=x
2
+(y−5)
2
3x
2
−(y−5)
2
=0
3x
2
−y
2
+10y−25=0
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