Question

The equation whose roots are 0, 0, 2, 2, 2, -2 is

Answer 1

Step-by-step explanation:

The equation whose roots are 0,0,2,2,-2,-2 is

(x-0)(x-0)(x-2)(x-2)(x+2)(x+2) = 0

${x}^{2} ( {x - 2)}^{2} ( {x + 2)}^{2} = 0$

${x}^{2} ( {x}^{2} - 2 \times x \times 2 + {2}^{2} )( {x}^{2} + 2 \times x \times 2 + {2}^{2} ) = 0$

${x}^{2} ( {x}^{2} - 4x + 4)( {x}^{2} + 4x + 4) = 0$

${x}^{2} ( {x}^{4} + 4 {x}^{3} + 4 {x}^{2} - 4 {x}^{3} - 16 {x}^{2} - 16x + 4 {x}^{2} + 16x + 16) = 0$

${x}^{2} ( {x}^{4} - 8 {x}^{2} + 16) = 0$

or

${x}^{6} - 8 {x}^{4} + 16 {x}^{2} = 0$

Answer 2

Answer:

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