the equation whose roots are 1,-1,3 is
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Given roots are 1, -1, 3
sum of roots is 1 -1 +3 = 3
product of roots 3(-1)(1)= - 3
let a, b,c are roots then equation is
x³- (a+b+c)x²+ ( ab+bc+ca)x -abc=0
a=1,b= -1,c=3
a+b+c= +3 +1 -1 =3
ab+bc+ca= 1(3)+3(-1)+1(-1)=3 - 3 -1= -1
abc= -3
Equation is x³-(3)x+( -1 )x +( - 3)=
x³-3x-x-3
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