Math, asked by priya5573, 2 months ago

the equation whose roots are multiplied by2 of those of x^3+3x^2-5x+7=0 is​

Answers

Answered by NamanPanchal
0

Answer:

Correct option is

A

x3+6x2−20x+8=0

The given equation is

f(x)=x3+3x2−5x+1=0

Replace x by 2x in the above equation to get the desired equation.

The required equation is

f(2x)=(2x)3+3(2x)2−5(2x)+1=0

=8x3+43x2−25x+1=0

On solving the equation, we get

x3+6x2−20x+8=0

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