The equation whose roots are squares of the roots of the equation 2x*x + 3x +1=0 is??
Answers
Answered by
1
hope this helps
please mark my answer brainliest.
please mark my answer brainliest.
Attachments:
Answered by
3
2x^2 + 3x + 1
spilting the middle term:
=> 2x^2 + 2x + x + 1
= 2x (x + 1) + 1 (x + 1)
= (2x + 1) (x + 1)
α1 = 2x + 1
= -1/2
β1 = x + 1
= -1
we know that the new roots are the square of previous roots
therefore α2 = α1^2
= (-1/2)^2
= 1/4
β2 = β1^2
= (-1)^2
= 1
we know that α2+ β2 = 1/4 + 1
= 5/4 = -b/a
α2*β2 = 1/4*1
= 1/4 = c/a
therefore a = 4 , b = -5 and c = 1
therefore the required equation is 4x - 5y + 1
Hope this hepls you :)
spilting the middle term:
=> 2x^2 + 2x + x + 1
= 2x (x + 1) + 1 (x + 1)
= (2x + 1) (x + 1)
α1 = 2x + 1
= -1/2
β1 = x + 1
= -1
we know that the new roots are the square of previous roots
therefore α2 = α1^2
= (-1/2)^2
= 1/4
β2 = β1^2
= (-1)^2
= 1
we know that α2+ β2 = 1/4 + 1
= 5/4 = -b/a
α2*β2 = 1/4*1
= 1/4 = c/a
therefore a = 4 , b = -5 and c = 1
therefore the required equation is 4x - 5y + 1
Hope this hepls you :)
Similar questions