Math, asked by murmupratima2904, 3 months ago

The equation (x + 1)^2=x^2 is ...... a quadratic equation.​

Answers

Answered by sainiinswag
1

Answer:

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This is not a quadratic equation.

Step-by-step explanation:

(x + 1)^2=x^2 \\  \\  {x}^{2}  + 2x + 1 =  {x}^{2}  \\  \\  {x}^{2}  + 2x + 1  -   {x}^{2} = 0 \\  \\ 2x + 1 = 0 \\  \\ this \: is \: not \: a \: quadratic \: equation \\  \\ this \: is \: ur \: required \: answer \: :):):):):)

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because in quadratic equation the power of variable should be 2

Answered by Skyllen
5

Given that, (x + 1)² = x²

(x)² + (1)² + 2(x)(1) = x²

x² + 1 + 2x = x²

x² - x² + 1 + 2x = 0

1 + 2x = 0

And 1+2x=0 Quadratic Equation!

Hence,

The equation (x + 1)^2=x^2 is not a quadratic equation.

Identity used:-

(a+b)² = a² + b² + 2ab

Explanation:-

• As we know that a equation that has the highest power of 2 is called a quadratic equation. But in our case, there wasn't any power of square (²).

• Quadratic equations are also called two-degree equations.

• A simple base equation for quadratic equation is ax²+bx+c.

And in the quadratic equation, the terms are as follows:- x² = a, x = b, and a constant term = c.

• Example of quadratic equation:-

  • 7x² + 3x + 9
  • This equation has:- a = 7, b = 3 and c = 9.
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