The equation (x+2)=0 has real roots
Answers
Answered by
1
Step-by-step explanation:
1 answer
centre of cirlce ( α+β2 , γ+δ2 ) → ( - a, - p ) Radius of circle = 12√((α-β)2+ (γ-δ)2) = 12√((α+β)2-4αβ+ (γ+δ)2-4γδ) = 12√(4a2-4b2+4p2-4 ...
Top answer
Similar questions