Question

The equation x^2 – 16x + k = 0 has exactly one real solution for what value of k?

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Answer 1

Answer:

I don't no

Step-by-step explanation:

sorry friend

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Answer 2

Answer:

k = 64

Step-by-step explanation:

x^2 - 16x + k = 0

on equating with ax^2 + bx + c =0

a = 10=, b = -16, c = j

D = b^2 - 4ac

= (-16)^2 - 4(1)(k)

= 256 - 4k

but , b^2 - 4ac = 0

256 - 4k = 0

4k = 256

k = 256/4

k = 64

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