the equation x^2+4x+3=0 has how many positive roots
Answers
Answered by
1
Answer:
Explanation:
x
2
−
4
x
−
3
is of the form
a
x
2
+
b
x
+
c
, with
a
=
1
,
b
=
−
4
and
c
=
−
3
.
This has discriminant
Δ
given by the formula:
Δ
=
b
2
−
4
a
c
=
(
−
4
)
2
−
(
4
×
1
×
−
3
)
=
16
+
12
=
28
=
2
2
⋅
7
This is positive but not a perfect square, so
x
2
−
4
x
−
3
=
0
has two distinct irrational roots.
Use the quadratic formula to give the roots:
x
=
−
b
±
√
b
2
−
4
a
c
2
a
=
−
b
±
√
Δ
2
a
=
4
±
2
√
7
2
=
2
±
√
7
Answer link
Answered by
0
Step-by-step explanation:
no positive roots
x^2+4x+3=0
x(x+3)+1(x+3)=0
(x+1)(x+3)=0
x= -1 or x = -3
these are negative value
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