Math, asked by ashishpatel3966, 16 hours ago

the equation x^2+4x+3=0 has how many positive roots​

Answers

Answered by duttasourik25
1

Answer:

Explanation:

x

2

4

x

3

is of the form

a

x

2

+

b

x

+

c

, with

a

=

1

,

b

=

4

and

c

=

3

.

This has discriminant

Δ

given by the formula:

Δ

=

b

2

4

a

c

=

(

4

)

2

(

4

×

1

×

3

)

=

16

+

12

=

28

=

2

2

7

This is positive but not a perfect square, so

x

2

4

x

3

=

0

has two distinct irrational roots.

Use the quadratic formula to give the roots:

x

=

b

±

b

2

4

a

c

2

a

=

b

±

Δ

2

a

=

4

±

2

7

2

=

2

±

7

Answer link

Answered by greatanushelshiyay
0

Step-by-step explanation:

no positive roots

x^2+4x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x= -1 or x = -3

these are negative value

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