The equation x^2-(p+4)x+2p+5=0 has equal roots the value of p
Answers
Answered by
72
x²-(p+4)x+2p+5=0
For equal roots
D=0
b²-4ac=0
[-(p+4)]²-4×1×(2p+5)=0
p²+16+8p-8p-20=0
p²-4=0
p²=4
p=±√4
p=+2 or p=-2
For equal roots
D=0
b²-4ac=0
[-(p+4)]²-4×1×(2p+5)=0
p²+16+8p-8p-20=0
p²-4=0
p²=4
p=±√4
p=+2 or p=-2
abhi569:
So, x = -2 Or x = 2
I can't edit it now.. it has been reported.. only one last step is missing i.e. ,p=-2 and p=+2
ya it is incomplete
relly very very sry for that plzzzz sryyy
hahaha... U will get the edit option soon.... Kl yaad dila dena.... Kl means 2bje ke baad Subah
okay bhai...
Correct it
Correction done...
(-:
(^_^)
Answered by
25
hey here your answer
so it's. D will be 0
D = b^2 - 4ac
(p+ 4) ^2 - 4 × 1 × (2p + 5) = 0
p^2 + 16 + 8p - 8p - 20 =0
p^2 -4 =0
p^2 = 4
p = + 2 and - 2
hope this helps✌✌
_____________________________
thanks; D
so it's. D will be 0
D = b^2 - 4ac
(p+ 4) ^2 - 4 × 1 × (2p + 5) = 0
p^2 + 16 + 8p - 8p - 20 =0
p^2 -4 =0
p^2 = 4
p = + 2 and - 2
hope this helps✌✌
_____________________________
thanks; D
Similar questions