The equation x2+2xy+4=0 is transformed to the parallel axes through the point (6,@) . For what value of @, its new form passes through the origin
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2
Answer:
which class topic is this.❓
Answered by
0
Answer:
-10/2
Step-by-step explanation:
x^2+2xy+4=0
(6)^2+2(6)a+4=0
36+12a+4=0
a=-10/2
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