The equation x2-(p+4)x+2p+5=0 has equal root the values of p will be
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Question : The equation x² - ( p + 4 )x + 2p + 5 = 0 ha equal root the value of p will be ?
Solution :
The given equation is : x² - ( p + 4 )x + 2p + 5.
Here ,
A = Coefficient of x² = 1
B = Coefficient of X = -p - 4.
And,
C = Constant term = 2p + 5.
Discriminant ( D ) = 0
b² - 4ac = 0
( -p - 4 )² - 4 * 1 * 2p + 5 = 0
(-p)² + 4² - 2*(-p)*4 - 8p - 20 = 0
p² + 16 + 8p - 8p - 20 = 0
p² - 4 = 0
p² = 4
p = √4
p = 2 or -2.
therefore the values of p is equal to 2 or -2.
Hope it helps you ♥
By Rishi 403.
BeBrainly..
Here is your answer !!
Question : The equation x² - ( p + 4 )x + 2p + 5 = 0 ha equal root the value of p will be ?
Solution :
The given equation is : x² - ( p + 4 )x + 2p + 5.
Here ,
A = Coefficient of x² = 1
B = Coefficient of X = -p - 4.
And,
C = Constant term = 2p + 5.
Discriminant ( D ) = 0
b² - 4ac = 0
( -p - 4 )² - 4 * 1 * 2p + 5 = 0
(-p)² + 4² - 2*(-p)*4 - 8p - 20 = 0
p² + 16 + 8p - 8p - 20 = 0
p² - 4 = 0
p² = 4
p = √4
p = 2 or -2.
therefore the values of p is equal to 2 or -2.
Hope it helps you ♥
By Rishi 403.
BeBrainly..
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