Question

The equation x² px +q=0p, qe R has no real roots if: (a) p² > 4q (b) p² <4q (c) p² = 4q (d) None of these​

Answer 1

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HERE IS UR ANSWER

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The equation x² px +q=0p, qe R has no real roots only if: p² <4q

option b) is correct answer