Question

The equation y=Ae^3x+Be^5x can be represented as *

(a) y^''-8y^'+5y=0

(b) y^''-8y^'=0

(c) y^'+8y^'=0

(d) y^''+8y^'+5y=0​

Answer 1

Answer:

y^'+8y'=0

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Answer 2

Answer:

Option (C) is the correct answer...