The equations 2x square + bx + c + 1 is equal to zero b, c belongs to cube and x square + 3 x minus 5 have common roots then value of b minus c is
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Suppose, α be the common root of the equations
x²+2x+3=0
and ax²+bx+c=0
Therefore α²+2α+3=0
Or, α²=-(2α+3) ····(1)
And aα²+bα+c=0
Or, aα²=-(bα+c)
Or, α²=-(bα+c)/a·····(2)
from (1) and (2) we get
-(bα+c)/a =-(2α+3)
bα/a+c/a=2α+3
comparing both sides we have
b/a=2
Or b=2a
and c/a=3
Or, c=3a
Now a:b:c=a:2a:3a
Or, a:b:c=1:2:3
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