The equations (b - C)x +(c - a)y+ (a - b) = 0
and (b³ - c³)x + (c³- a³)y + (a³ - b³) = 0 will
represent the same line if
(a) b + c = 0
(b) b = c, c = a and a = b or a + b + c = 0
(c) a + b = 0
(d) a + b + c #0
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Answer:
here is your answer
Step-by-step explanation:
The given equations are in the form ax+by+c=0 and px+qy+r=0 who represent the same line.
So,
p
a
=
q
b
=
r
c
=k when, k is a constant.
Here a=b
3
−c
3
,b=c
3
−a
3
,c=a
3
−b
3
and p=b−c,q=c−a,r=a−b
∴
b−c
b
3
−c
3
=k
⇒(b−c)(b
2
+c
2
+bc)=(b−c)k
⇒(b−c)(b
2
+c
2
+bc−k)=0
∴ either b−c=0
⇒b=c .......(i)
or (b
2
+c
2
+bc−k)=0
⇒b
2
+c
2
+bc=k ............(1)
Similarly c=a........(ii) and
c
2
+a
2
+ca=k ............(2)
Also a=b .......(iii) and
a
2
+b
2
+ab=k ............(3)
∴ from (i), (ii) and (iii), we have
a=b=c first condition
Again from (1) and (2), we have
b
2
+c
2
+bc=c
2
+a
2
+ca
⇒b
2
−a
2
=c(a−b)
⇒(b−a)(b+a)=c(a−b)
⇒b+a=−c
⇒a+b+c=0 second condition, we shall get the same considering (2) and (3).
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