Question

The equations kx-y=2, 2x-3y=-,3x-2y+1=0 are consistent for
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Answer 1

Answer:

For a system of equations a

1

x+b

1

y+c

1

=0;a

2

x+b

2

y+c

2

=0 to have unique solution, the condition to be satisfied is

a

2

a

1



=

b

2

b

1



=

c

2

c

1

⇒

6

k



=

−2

−1



=

3

2

∴ For unique solution of system of equations, k



=3,4

Step-by-step explanation:

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