Question

The equations of lines with slope 3 and the length of the perpendicular from the origin equal to √ 10 are
a)x=y+10
b)y=2x−5
c)y=3x+10
d)x=3y−10
e)y=3x−10
f)x=3y+10

Answer 1

Answer:

$x + 3y = 10$

Step-by-step explanation:

$m = 3 \\ \\ \tan( \alpha ) = 3 \\ \\ \sin( \alpha ) = \frac{3}{ \sqrt{10} } \\ \\ \cos( \alpha ) = \frac{1}{ \sqrt{10} } \\ \\ x \cos( \alpha ) + y \sin( \alpha ) = p \\ \\ x( \frac{1}{ \sqrt{10 } } ) + y( \frac{3}{ \sqrt{10} } ) = \sqrt{10} \\ \\ x + 3y = 10$

Answer 2

Answer:

Two Answers

y=3x+10

y=3x-10

Step-by-step explanation:

video: remove spaces

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