The equations of perpendiculars of the sides AB & AC of triangle ABC are x - y - 4 = 0 and
2x-y-5=0 respectively. If the vertex Ais (-2, 3) and point of intersection of perpendiculars bisectors is (3/2,5/2),
find the equation of medians to the sides AB & AC respectively.
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Bro I am not getting idea but
I successfully got the three vertices (-2,3), (2,-1),(2,1)
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