the equations of x+y+z=0 2x-3y-3z=0 3x-5y+4z have
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Answer:
Given Equations:
2x + 3y + 4z = 0
X + y + z = 0
2x + 5y – 2z = 0
Any system of equation can be written in matrix form as AX = B
Now finding the Determinant of these set of equations,
= 2(1×(– 2) – 1×5) – 3(1×(– 2) – 2×1) + 4(1×5 – 2×1)
= 2(– 2 – 5) – 3(– 2 – 2) + 4(5 – 2)
= 1×(– 7) – 3 × (– 4) + 4×3
= – 7 + 12 + 12
= 17
Since D ≠ 0, so the system of equation has infinite solution.
Therefore the system of equation has only solution as x = y = z = 0.
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