the equestion (x-2)²+1=2x-3
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x2+4-4x+1=2x-3
x2-4x-2x+5+3=0
x2-6x+8=0
x2-4x-2x+8=0
x(x-4)-2(x-4)=0
(x-4)(x-2)=0
x-4=0 or x-2=0
x=4 or x=2
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Answered by
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Step-by-step explanation:
x^2 + 4 - 4x +1 = 2x -3
x^2 + 5-4x -2x = -3
x^2-6x = -3-5
x^2-6x +8
x^2-4x -2x +8
x(x -4) -2(x-4)
(x-2) (x-4)
x= 2,4
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