Question

The equilibrium concentration of X, Y and YX2 are
4,2 and 2 moles respectively for the equilibrium
2X + Y = YX2. The value of Kc is.​

Answer 1

Answer:

Explanation:

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Answer 2

The value of $K_c$ is 0.125

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For a general chemical reaction:

$2X+Y\rightarrow YX_2$

The expression for $K_c$ is written as:

$K_{c}=\frac{[YX_2]^2}{[X]^2[Y]^1}$

Putting in the values we get:

$K_{c}=\frac{[2]^2}{[4]^2[2]^1}$

$K_{c}=0.125$

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