Question

The equilibrium constant for, 2h2s(g)⇌2h2(g)+s2(g) is 0.0118 at 1300 k while the heat of dissociation is 597.47 kj. the standard equilibrium constant of the reaction at 1200 k is

Answer 1

Dear friend,


● Answer -
Kc = 0.183

● Explanation -
For reaction,
2H2S ---> 2H2 + S2
∆n = 3 - 2
∆n = 1

Relationship between Kp & Kc is given by formula -
Kp = Kc(RT)^∆n

Rearranging for Kc,
Kc = Kp(RT)^-∆n

Substitute values,
Kc = 0.0118 (8.314×1200)^-1
Kc = 0.183

Therefore, Kc at 1200 K is 0.183.

Hope this helps you...

Answer 2

Answer:

1.18

here's the answer and hope this helps you.