Chemistry, asked by nitinkrsingh0, 8 months ago

the equilibrium constant for a reaction is SO2(g)+1÷2 O2 (g) ⇄ SO3(g).

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Answered by abhinavsingh99626
0

Answer:

Consider the reaction: SO2(g) + 1/2 O2(g) SO3(g) Write the equilibrium constant for this reaction in terms of the equilibrium constants, Ka and Kb, for reactions a and b below:

a.) 2 S(s) + 3 O2(g) 2 SO3(g) ............. Ka

b.) S(s) + O2(g) SO2(g) ............. Kb

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