Question

The equilibrium constant for the reaction

A2(g)+B2(g)=2AB(g) is 64 at 600 K.

What is the equilibrium constant for

2AB=A2(g)+B2(g) at the same temperature?

Answer 1

Explanation:

A2+B2=2AB. K=64

SINCE REACTION PROCEEDS IN BACKWARD OR REVERSE DIRECTIONi.e,

2AB=A2+B2. K'=1/√K

K'=1/√64

K'=1/8

EQUILIBRIUM CONSTANT IS 1/8

Answer 2

Answer:

1/64

Explanation:

the equilibrium constant , Kc = 64

we know that , Kc = [AB]²/[A2] [B2]  = 64

here the equation is ; 2AB ⇆ A2(g) + B2(g)

here ; Kc'   = [A2] [B2] / [AB]² = 1/{ [AB]²/ [A2] [B2] }

                                                =  1/ 64

hence, the equilibrium constant will be = 1/64