The equilibrium constant for the reaction
AB is
K. The equilibrium constant for the reaction
mA mB is
Answers
Answered by
0
Answer:
Please give the complete reaction
Answered by
2
Answer:
K^m
Explanation:
Let K is the equilibrium constant for the reaction, A⇔B.
Let K be the equilibrium constant for the reaction, mA⇔mB.
K = B ÷ A
B = KA
K′ = B^m ÷ A^m
Substituting B=KA in the expression for K ′, we get
K ′= B^m ÷ A^m
= (KA)^m ÷ A^m
= K^m × (A^m ÷ A^m)
= K^m
K ′ = K^m
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