Question

The equilibrium constant for the reaction
Cu(s) + 2Ag+ (aq) = Cu2+ (aq) + 2Ag (s)
is 2.0 x 10¹⁵ at 298 K. Find the equilibrium
concentration of Cu2+ (aq) if that of Ag (aq) is
1.0 x 10-11 mol L-1​

Answer 1

Answer:

Cu(s)+2Ag

2+

(aq)⟶Cu

2+

(aq)+2Ag(s)

E

o

=0.46V at 298K

logK

C

=

RT

nFE

o

=

0.059

2×0.46

K

C

=4×10

15

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