the equilibrium constant for the reaction i2 +cl2 = 2icl at 740k is 640
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Methane, ethyne, and hydrogen form the following equilibrium mixture.2CH
4(g)
⇀↽
C
2
H
2(g)
+
3H
2(g)
While studying this reaction mixture, a chemist analysed a 4.0 L sealed flask at1700˚C. The chemist found 0.46 mol of CH
4(g)
, 0.64 mol of C
2
H
2(g)
, and 0.92 molof H
2(g)
. What is the value of
K
c
for the reaction at 1700˚C?
What Is Required?
You need to calculate the value of
K
c
.
What Is Given?
You have the chemical equation and the amount of each substance at equilibriumin a 4.0 L flask.
Plan Your Strategy
Step 1
Calculate the molar concentration of each compound at equilibrium.
Step 2
Write the equilibrium expression. Then substitute the equilibrium molarconcentrations into the expression.
Act on Your Strategy
Step 1
The reaction takes place in a 4.0 L flask. Calculate the molar concentrationsat equilibrium.[CH
4
]
=
0.46mol4.0L
=
0.115mol/L[C
2
H
2
]
=
0.64mol4.0L
=
0.16mol/L[H
2
]
=
0.92mol4.0L
=
0.23mol/L
Step 2
Write the equilibrium expression. Substitute the equilibrium molarconcentrations into the expression.
K
c
=
[C
2
H
2
][H
2
]
3
[CH
4
]
2
=
(0.16)(0.23)
3
(0.115)
2
=
0.15
4(g)
⇀↽
C
2
H
2(g)
+
3H
2(g)
While studying this reaction mixture, a chemist analysed a 4.0 L sealed flask at1700˚C. The chemist found 0.46 mol of CH
4(g)
, 0.64 mol of C
2
H
2(g)
, and 0.92 molof H
2(g)
. What is the value of
K
c
for the reaction at 1700˚C?
What Is Required?
You need to calculate the value of
K
c
.
What Is Given?
You have the chemical equation and the amount of each substance at equilibriumin a 4.0 L flask.
Plan Your Strategy
Step 1
Calculate the molar concentration of each compound at equilibrium.
Step 2
Write the equilibrium expression. Then substitute the equilibrium molarconcentrations into the expression.
Act on Your Strategy
Step 1
The reaction takes place in a 4.0 L flask. Calculate the molar concentrationsat equilibrium.[CH
4
]
=
0.46mol4.0L
=
0.115mol/L[C
2
H
2
]
=
0.64mol4.0L
=
0.16mol/L[H
2
]
=
0.92mol4.0L
=
0.23mol/L
Step 2
Write the equilibrium expression. Substitute the equilibrium molarconcentrations into the expression.
K
c
=
[C
2
H
2
][H
2
]
3
[CH
4
]
2
=
(0.16)(0.23)
3
(0.115)
2
=
0.15
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