Question

The equilibrium constant for the reaction is 10. Calculate the value of ∆ G° at 27°C

Answer 1

Answer:

if this is your question then

The equilibrium constant for a reaction is 10. What will be the value of ΔG0 ?

values(we know)

R = 8.314 JK–1 mol–1, T = 300 K.

From the expression, ΔG0 = -2.303 RT log Keq

ΔG0 for the reaction,

= (2.303) (8.314 JK-1mol-1) (300 K) log10

= -5744.14 Jmol-1

= -5.744 kJ mol-1

Explanation:

hope this helps