Question

the equilibrium constant for the reaction n2(g)+3h2(g)⇌2nh3(g) is K. what will be the equilibrium constant for the reaction involving decomposition of one mole of ammonia?

Answer 1

Answer: The equilibrium constant for the reaction involving decomposition of one mole of ammonia is:

$K'=\frac{1}{K}$

Explanation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

The equilibrium constant will be given as :

$K=\frac{[NH_3]^2}{[N_2][H_2]^3}$

Now the equilibrium constant for the reaction of decomposition of 1 mole of ammonia:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

$K'=\frac{[N_2][H_2]^3}{[NH_3]^2}=\frac{1}{K}$

The equilibrium constant for the reaction involving decomposition of one mole of ammonia is:

$K'=\frac{1}{K}$

Answer 2

Explanation:

A+3B-----2X,K=x what will be the equilibrium constant for the decomposition of one mol of X