Question

The equilibrium constant for the reaction N2(g) + O2(g) + 2NO(g) at temperature T is 4x10^⁴. The value of Kc for the reaction NO(g)gives ½N2(g) +½O2 at the same temperature is
(A) 2.5 × 10² (B) 50
(C) 4 x 104
(D) 0.02​

Answer 1

Answer:

Explanation:

Answer is B

Answer 2

Answer:(B)

Explanation:

Let N2+O2---2NO____eqn1

Its value of K1 is given i.e 4×10^-4

And

NO---  1/2N2+1/2O2_____eqn2 and we have to find Kc for this reaction

Eqn 2 can be written as the reverse of eqn 1 and 1/2 times of the eqn 1

i.e,

The value of Kc can be written as

Kc =  (1/K1)^1/2

By putting the values

Kc = (1/10^-4×4)^1/2

Kc=50

Hope it helps you