Question

The equilibrium constant for the reaction N2(g)+O2(g) gives 2NO(g) at temperature T is 4x10^⁴.The value of Kc for the reaction NO (g) gives ½N2 (g)+½O2at the same temperature is
(A) 2.5 x 10² (B) 50
(C) 4x 104
(D) 0.02​

Answer 1

Answer:

Explanation:

Answer is B 50

Answer 2

The value of $K_c$ for the reaction $NO(g)\rightarrow \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)$  at the same temperature is $5\times 10^{-3}$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{eq}$

For a general chemical reaction:

$N_2(g)+O_2(g)\rightarrow 2NO(g)$

The expression for $K_{eq}$ is written as:

$K_{c}=\frac{[NO]^2}{[N_2]^1[O_2]^1}$

$K_{c}=4\times 10^4$

For the reaction :

$NO(g)\rightarrow \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)$

That is the above reaction is reversed and halved, the new equilibrium constant is:

$K'_{c}=\frac{1}{\sqrt {K_c}}=\frac{1}{\sqrt {4\times 10^4}}=\frac{1}{200}=5\times 10^{-3}$

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