Question

The equilibrium constant for the reaction, so3(g) ⇌ so2(g) + 1/2o2(g), is kc = 4.9 × 10–2. the value of kc for the reaction, 2so2(g) + o2(g) ⇌ 2so3(g) will be

Answer 1

For reverse reaction equilibrium constant=1/(Kc)^2
So, new equilibrium constant = 1/(4. 9×10^-2)^2
=4. 16×10^2

Answer 2

Answer: 416.5

Explanation:

$SO_3\leftrightharpoons SO_2+\frac{1}{2}O_2$

$K_c=\frac{[SO_2][O_2]^{1/2}}{[SO_3]}=4.9\times 10^{-2}$

The new equation is formed by reversing the equation and multiplying by 2.

$2SO_2+O_2\leftrightharpoons 2SO_3$

$K_c'=\frac{1}{K_c^2}$

$K_c'=\frac{1}{(4.9\times 10^{-2})^2}=416.5$