Question

the equilibrium constant for the reaction w + x = y + z is 9 if one mole of each of w and x are mixed and there is no chnge in volume the no. of moles of y formed is​

Answer 1

Answer:3/4 mole for a given volume

Explanation:

Given in the image

Answer 2

The number of moles of y formed is​ $\frac{3}{4}$

Explanation:

Equilibrium constant is the ratio of the concentration of products to the concentration of reactants each term raised to its stochiometric coefficients.

Let the volume be = 1L

Initial concentration of w =$\frac{moles}{Volume}=\frac{1mol}{1L}=1M$

Initial concentration of x =$\frac{moles}{Volume}=\frac{1mol}{1L}=1M$

The given balanced equilibrium reaction is,

                 $w+x\rightleftharpoons y+z$

                   

At t=0            1M    1M       0        0

at, t=eqm      (1-x)M   (1-x)M     (x)M   (x)M

The expression for equilibrium constant for this reaction will be,

$K_c=\frac{[y]\times [z]}{[w]\times [x]}$

Putting in the values

$K_c=\frac{(x)\times (x)}{(1-x)\times (1-x)}$

$9=\frac{(x)\times (x)}{(1-x)\times (1-x)}$

$x=\frac{3}{4}$

Thus number of moles of y formed = x = $\frac{3}{4}$

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