Question

The equilibrium constant K_{c}K c
​ of a reversible reaction is 10 .10. The rate constant for the reverse
reaction is 2.8 .2.8. What is the rate constant for forward reaction

Answer 1

Answer:

Answer

Kc=KbKf. Now Kc = 10, Kb = 2.8 

∴kf=10×2.8

∴Kf=28